Reemplazando x=2y, z=2y/3, en x+y+z=11 :
[tex]2y + y + \frac{2y}{3} = 11 [/tex]
[tex] \frac{3.3y}{3} + \frac{2y}{3} = 11[/tex]
[tex] \frac{9y}{3} + \frac{2y}{3} = \frac{11y}{3} [/tex]
[tex] \frac{11y}{3} = 11[/tex]
[tex]y = \frac{11.3}{11} [/tex]
[tex]y = 3[/tex]
[tex]x = 6[/tex]
[tex]z = \frac{2y}{3} = 2[/tex]
Reemplazando x,y,z en x+2y+2z.
[tex]6 + 2.3 + 2.2 = 16[/tex]
