HALLAR 1) 5(x-3) + 2 = 3X-5 7X-8 = 2x+12 2) J 3) 10x + 5 = 4x +35 7+12X= 2X + 27 5) 6) 8) 9 AV 3X 5 13) x" 15x+4-3X= 4X -6 - X-10 8x + 2(x-3) = 3(x+2) 9X - 3(7-X) = 5 + 2(2-x) X+5 12) (SX-1) 3 + 2 3 10) 5X 3 11) 3 (5x + 2) + 2 (3-X) = 5x + 2(18-7x) + 10 + = 5 2 1 2 THEY L 3 7x + 24 4X- 7 2 J3 11 11 L 6 +34 7x+2+ 4 48-5 2 3/90 8 در 3​