resolver: 1) (2x ^ 3 - 3) / (x - 1) =
2) (x ^ 3 + x + 10) / (x ^ 2 - 2x + 4) =
3 ) (12x ^ 5 + x ^ 3 - 5/3) / (6x ^ 2 - 3x + 5) =
4 (7x ^ 3 + 6x ^ 2 + 21x + 20) / (x ^ 2 + 3) =
5)(x-x²+놂): (乏x²-름)​