Respuesta :

[tex]\csc^2=\cot^2x+1[/tex]

[tex]\displaystyle \frac{1}{\sin^2x}= \frac{\cos^2x}{\sin^2x}+1 [/tex]

[tex]\displaystyle \frac{1}{\sin^2x}= \frac{\cos^2x+\sin^2x}{\sin^2x} [/tex]

[tex]\frac1{\sin^2x}=\frac1{\sin^2x} [/tex]

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