Respuesta :
[tex] \\\log\sqrt x-\log5=0.5\\ \log\frac{\sqrt x}{5}=\log10^{0.5}\\ \frac{\sqrt x}{5}=10^{0.5}\\ \sqrt x=5\cdot10^{0.5}\\ x=25\cdot10\\ x=250 [/tex]
porfavor urgente como resolver este logaritmo log raiz x - log 5=0.5
[tex] \\\log\sqrt x-\log5=0.5\\ \log\frac{\sqrt x}{5}=\log10^{0.5}\\ \frac{\sqrt x}{5}=10^{0.5}\\ \sqrt x=5\cdot10^{0.5}\\ x=25\cdot10\\ x=250 [/tex]