[tex]N=f(t)=1500\cdot 2^t
para N=543058 bacterias\\ \\
543058=1500\cdot2^t\\ \\despejamos\ 2^t\\ \\2^t=\frac{543058}{1500}\\ \\aplicamos\ logaritmo\ natural\\ \\ln(2^t)=ln(\frac{543058}{1500})\\ \\t\cdot ln(2)=ln(\frac{543058}{1500})\\ \\[/tex]
[tex]t=\frac{ln(\frac{543058}{1500})}{ln(2)}\\ \\t=8,4999...\\ \\t\approx8,5 horas[/tex]