Respuesta :

(x+m)(x+1)-(x+1)(x-n)=(x+1)[(x+m)-(x-n)] =(x+1)(x+m-x+n)=(x+1)(m+n)

(1+3a)(x+1)-2a(x+1)+2(x+1)=(x+1)(1+3a-2a+3)=(x+1)(a+4)
lizipalmer


   (xx+x.1+mx+m.1)-(xx-xn+1n)= (x+1) {x+m-x+n}

   (3a+1) (x+1)-2a(x+1)+2(x+1) =(x+1) (3a-2a+1+3)

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