Respuesta :
Método de igualdad
6x + 3y = 39 Ec1
2x - 3y = 1 Ec2
x1 = 39 - 3y/6
x2 = 1 + 3y/2
39 - 3y 1 + 3y
_____ = ______
6 2
2 (39 - 3y) = 6 (1 + 3y)
78 - 6y = 6 + 18y
-6y - 18y = 6 - 78
(-) -24y = -72
24y = 72
y = 72/24
y = 3
6x + 3y = 39 Ec1
6x + 3(3) = 39
6x + 9 = 39
6x = 39 - 9
6x = 30
x = 30/6
x = 5
2x - 3y = 1 Ec2
2x - 3(3) = 1
2x - 9 = 1
2x = 1 + 9
2x = 10
x = 10/2
x = 5
x = 5 ; y = 3
Comprobación
6x + 3y = 39 Ec1
6(5) + 3(3) = 39
30 + 9 = 39
39 = 39
2x - 3y = 1 Ec2
2(5) - 3(3) = 1
10 - 9 = 1
1 = 1
Espero haberte ayudado. Suerte en los estudios ≧◠◡◠≦.