Respuesta :
x(x+1)= 132
x^2 + x - 132 = 0
Δ= b^2 - 4ac
Δ= 1 - 4*1*-132
Δ= 1 + 528
Δ=529
√Δ=23
[tex] x_{1}= \frac{-1 + 23}{2}= \frac{22}{2}= 11 \\ x_{2}= \frac{-1 - 23}{2} = - \frac{24}{2}= -12 [/tex]
11*12 = 132
tus numeros son 11 y 12
x^2 + x - 132 = 0
Δ= b^2 - 4ac
Δ= 1 - 4*1*-132
Δ= 1 + 528
Δ=529
√Δ=23
[tex] x_{1}= \frac{-1 + 23}{2}= \frac{22}{2}= 11 \\ x_{2}= \frac{-1 - 23}{2} = - \frac{24}{2}= -12 [/tex]
11*12 = 132
tus numeros son 11 y 12