Respuesta :
angulos suplementarios suman 180°
alfa = x
beta = 180° -x
x= 6(180°-x)
x=1080°-6x
x+6x =1080°
7x=1080°
x=1080°/7
x= 154,2857°
alfa0 154.2857°
beta = 180° -154,2857° =25,7143°
alfa = x
beta = 180° -x
x= 6(180°-x)
x=1080°-6x
x+6x =1080°
7x=1080°
x=1080°/7
x= 154,2857°
alfa0 154.2857°
beta = 180° -154,2857° =25,7143°
