Los valores de los elementos que le faltan a los triangulos oblicuoangulos son respectivamente:
Triángulo 1: b = 10.98 ; c = 13.44 ; A = 75°
Triángulo 2: b = 250.77 ; A = 45.9° ; B = 33.65°
Triángulo 3: c = 74.11 ; b = 59.37 ; A = 57°
Triángulo 4: a= 36.61 ; b = 26.48; A = 77.78
Aplicando la ley de seno : a/senA = b/senB = c/senC , se obtienen los siguientes resultados:
Triángulo 1 : a = 15
A = 180° -B-C =180 -45° -60° = 75°
a/senA = b/senB
b = a*senB/senA = 15*sen45°/sen75° = 10.98
a/senA = c/senC
c = a*senC/senA = 15*sen60°/sen75° =13.44
Triángulo 2:
a/senA= c/senC
senA= a*senC /c = 325*sen100.45°/445 ⇒ A = 45.9°
B = 180° -A -C = 180° - 45.9°- 100.45° = 33.65°
b = a*senB/senA = 325*sen33.65°/sen45.9° = 250.77
Triángulo 3:
A = 180° -B-C =180 -50° -73° = 57°
a/senA = b/senB
b = a*senB/senA = 65*sen50°/sen57° = 59.37
a/senA = c/senC
c = a*senC/senA = 65*sen73°/sen57° =74.11
Triángulo 4:
A = 180° -B-C =180 -45° -57.22° = 77.78°
a= c*senA/senC = 31.5*sen77.78°/sen57.22°= 36.61
b = a*senB/senA = 36.61*sen45°/sen77.78° =26.48