Respuesta :
Explicación:
1)
5,5 = -log[H+]
[H+] = 3,162*10^-6 molar
2)
4 = -log[OH-]
[OH-] = 1*10^-4 molar
3)
1,8 = -log[H+]
[H+] = 0,0158 molar
Explicación:
1)
5,5 = -log[H+]
[H+] = 3,162*10^-6 molar
2)
4 = -log[OH-]
[OH-] = 1*10^-4 molar
3)
1,8 = -log[H+]
[H+] = 0,0158 molar