Respuesta :
a) 943.57mol Na₂CO₃ * 2mol NaOH / 1mol Na₂CO₃ = 1,887.14mol NaOH
b) 943.57mol Na₂CO₃ * 1mol Ca(OH)₂ / 1mol Na₂CO₃ = 943.57mol Ca(OH)₂
d) 5mol Ca(OH)₂ * 2mol NaOH / 1mol Ca(OH)₂ = 10mol NaOH
b) 943.57mol Na₂CO₃ * 1mol Ca(OH)₂ / 1mol Na₂CO₃ = 943.57mol Ca(OH)₂
d) 5mol Ca(OH)₂ * 2mol NaOH / 1mol Ca(OH)₂ = 10mol NaOH