Respuesta:
1/6 de m de 1 caja
1/2 de m de 1 caja
1/6 * m/1 + 1/2 * m/1 = x + 12
[tex]\frac{1*m}{6*1} + \frac{1*m}{2*1}[/tex]
= m / 6 + m / 2 = x + 12
[tex]\frac{m + 3m}{6}[/tex] = 4m/6
4m / 6 = x + 12
4m= x + 12 * 6
4m = x + 72
m = x + 13
Reemplazamos
1/6 * x + 13/1 + 1/2 * x + 13/1 = x +12
[tex]\frac{1(x+13)}{6} + \frac{1(x+13)}{2} \\\\\frac{x + 13}{6} + \frac{x + 13}{2} \\\\\frac{x + 13 + 3x + 39}{6} \\\\\frac{4x + 52}{6}[/tex]= x + 12
4x + 52 = 6(x + 12)
4x + 52 = 6x + 72
52 - 72 = 6x - 4x
-20 = 2x
-20/2 = x
-10 = x
x = 10
Total 10 + 12 = 22 manzanas
