Respuesta:
Formulas a utilizar:
v= \sqrt{(vx) ^{2} + (vy)^2 }v=
(vx)
2
+(vy)
2
\begin{gathered}vx=vox \\ vy=voy+gt \\ voy=vo*sen \alpha \end{gathered}
vx=vox
vy=voy+gt
voy=vo∗senα
vox=vo*cos \alphavox=vo∗cosα
x = vox*tx=vox∗t
Operamos
voxvox
\begin{gathered}vox=vo*cos \alpha \\ vox=100m/s * cos45 \\ vox=100m/s * 0.7 \\ vox=70.71m/s\end{gathered}
vox=vo∗cosα
vox=100m/s∗cos45
vox=100m/s∗0.7
vox=70.71m/s
Ya sabemos que vx=70.71m/svx=70.71m/s
Operamos
\begin{gathered}voy = vo * sen \alpha \\ voy=100m/s *0.70 \\ voy=70.71m/s\end{gathered}
voy=vo∗senα
voy=100m/s∗0.70
voy=70.71m/s
Operamos
\begin{gathered}vy=voy+gt \\ vy=70.71m/s + 9.8m/s^2 * 14.43s \\ vy=70.71m/s+141.42m/s \\ vy=212.13m/s\end{gathered}
vy=voy+gt
vy=70.71m/s+9.8m/s
2
∗14.43s
vy=70.71m/s+141.42m/s
vy=212.13m/s
Para sacar el vector de velocidad resultante
\begin{gathered}v =\sqrt{(vx)^2+(vy)^2} \\ v=\sqrt{4999.90+4999.90} \\ v=\sqrt{9999.8} \\ v=99.99 m/s\end{gathered}
v=
(vx)
2
+(vy)
2
v=
4999.90+4999.90
v=
9999.8
v=99.99m/s
Posicion a los 3s
\begin{gathered}x=vox*t \\ x=70.71m/s * 3 \\ x=212.13m\end{gathered}
x=vox∗t
x=70.71m/s∗3
x=212.13m
Posicion a los 8s
\begin{gathered}x=vox*t \\ x=70.71m/s * 8 \\ x=565.68m\end{gathered}
x=vox∗t
x=70.71m/s∗8
x=565.68m
