[tex]area \: de \: un \: trapecio\\ a = ( \frac{b + \beta }{2} ) \times h \\ a = ( \frac{12 + 18}{2} ) \times 8 \\ a = ( \frac{30}{2} ) \times 8 \\ a = 15 \times 8 \\ a = 120 \\ \\ perimetro \: de \: un \: trapecio \\ p = \beta + b + h + ( \sqrt{{h}^{2} + { (\beta - b)}^{2} } \\ p = 18 + 12 + 8 + ( \sqrt{ {8}^{2} + {(18 - 12)}^{2} } \\ p = 38 + \sqrt{64 + 36} \\ p = 38 + 10 \\ p = 48[/tex]
el perimetro es 48cm
el área es 120cm2
