Explicación paso a paso:
hola!
Calcular la hipotenusa de los siguientes triángulos !
1=
[tex]x = \sqrt{ {3}^{2} + {4}^{2} } [/tex]
[tex]x = \sqrt{9 + 16} [/tex]
[tex]x = \sqrt{25} [/tex]
[tex]x = 5cm[/tex]
2=
[tex]x = \sqrt{ {12}^{2} + {9}^{2} } [/tex]
[tex]x = \sqrt{144 + 81} [/tex]
[tex]x = \sqrt{225} [/tex]
[tex]x = 15cm[/tex]
3=
[tex]x = \sqrt{ {15}^{2} + {8}^{2} } [/tex]
[tex]x = \sqrt{225 + 64} [/tex]
[tex]x = \sqrt{289} [/tex]
[tex]x = 17m[/tex]
4=
[tex]x = \sqrt{ {24}^{2} + {20}^{2} } [/tex]
[tex]x = \sqrt{576 + 400} [/tex]
[tex]x = \sqrt{976} [/tex]
[tex]x = 31.24dm[/tex]
espero te sirva saludos
