Respuesta :
Respuesta:
Datos
F = 550 N
Fr = 40 N
Masa = 68 Kg
a = ?
a= \dfrac{F-Fr}{m} = \dfrac{550N-40N}{68kg} = \dfrac{510kg\cdot m/s^2}{68kg} =\bf 7,5m/s^2a=
m
F−Fr
=
68kg
550N−40N
=
68kg
510kg⋅m/s
2
=7,5m/s
2
Respuesta:
Datos
F = 550 N
Fr = 40 N
Masa = 68 Kg
a = ?
a= \dfrac{F-Fr}{m} = \dfrac{550N-40N}{68kg} = \dfrac{510kg\cdot m/s^2}{68kg} =\bf 7,5m/s^2a=
m
F−Fr
=
68kg
550N−40N
=
68kg
510kg⋅m/s
2
=7,5m/s
2