El ejercicio a resolver es:
[tex]\huge \boxed{\sf{8x - 15 = 5x}}[/tex]
Ahora procedemos a desarrollar:
[tex]\bf{8x - 15 = 5x}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf 8x-15-\red{5x}=5x-\red{5x} \ \to \ \ Restar \ 5x \ de \ ambos \ lados.\end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf 3x-15=0 \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf 3x-15+\red{15}=0+\red{15} \ \to \ \ Sumar \ 15 \ a \ ambos \ lados. \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf 3x=15 \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf \dfrac{3x}{\red{3}}=\dfrac{15}{\red{3}} \ \to \ \ Dividir \ ambos \ lados \ por \ 3. \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf \red{x=5} \ \ \red{\Rightarrow} \ \ \ Respuesta \end{gathered}$}[/tex]
↓
[tex]\bf{\underline{Comprobacion:}}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf 8x-15=5x \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf 8\times5-15=5\times5 \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf 40-15=5\times5 \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf 40-15=25 \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf 25=25 \end{gathered}$}[/tex]
[tex]\underline{\pmb{Se \ cumple \ la \ igualdad.}}[/tex]
Saludos Estivie [tex][/tex]
