Respuesta:
[tex] {x}^{2} + {y}^{2} = {( \sqrt{11} )}^{2} [/tex]
[tex] {x}^{2} + {y}^{2} = 11[/tex]
[tex] {x}^{2} + {y}^{2} - 11 = 0[/tex]
Explicación paso a paso:
[tex]r = \frac{2 \sqrt{11} }{2} = \sqrt{11} [/tex]
[tex]{x}^{2} + {y}^{2} = {r}^{2} [/tex]
