Respuesta :

Yay78

Respuesta

Soluciónes:

  • A)    4x+32 = 0
  • B)    5y-5 = 0
  • C)    28x-168 = 0

Explicación paso a paso:

A) [tex]\frac{x+8}{2} = \frac{x-4}{6}+2[/tex]

[tex]\frac{x+8}{2} = \frac{x-4+12}{6}[/tex]

[tex]\frac{x+8}{2} = \frac{x+8}{6}\\[/tex]

[tex]6(x+8) = 2(x+8)[/tex]

[tex]6x+48 = 2x+16[/tex]

[tex]6x-2x+48-16 = 0[/tex]

[tex]4x+32 = 0[/tex]

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B)  [tex]3(y-5)-(8+2y) = 4(y-7)+2y[/tex]

[tex]3y-15-8-2y = 4y-28+2y = 0[/tex]

[tex]3y-2y-4y-15-8+28-2y = 0\\[/tex]

[tex]-5y+5 = 0\\[/tex]

[tex]5y-5 = 0[/tex]

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C) [tex]\frac{x-2}{2}+\frac{1}{7} = \frac{5x}{14}[/tex]

[tex]\frac{7(x-2)}{7(2)} +\frac{2*1}{7*2} = \frac{5x}{14}[/tex]

[tex]\frac{7x-14}{14}+\frac{2}{14} = \frac{5x}{14}[/tex]

[tex]\frac{7x-14+2}{14} = \frac{5x}{14}[/tex]

[tex]\frac{7x-12}{14} = \frac{5x}{14}[/tex]

[tex]14(7x-12) = 14(5x)[/tex]

[tex]98x-168 = 70x[/tex]

[tex]98x-70x-168 = 0[/tex]

[tex]28x-168 = 0[/tex]