Para este problema de MRU el espacio recorrido será igual que la distancia, por ello usaremos:
[tex]\boxed{\hphantom{A}\underset{\vphantom{.}}{\overset{\vphantom{A}}{\sf{d = vt}}}\hphantom{A}}\hspace{50 pt}\sf{Donde}\hspace{25 pt}\begin{array}{l}\sf{\circledast\quad \vphantom{\Big|}d:Distancia}\\\sf{\circledast\quad \vphantom{\Big|}v:Rapidez}\\\sf{\circledast\quad \vphantom{\Big|}t:Tiempo}\\\end{array}[/tex]
Extraemos los datos del problema:
[tex]\begin{array}{ccccccccccccccc}\sf{\boldsymbol{\bigcirc \kern-8pt\triangleright}\ \ \ t=0\ s}&&&&&&&&&&&&\sf{\boldsymbol{\bigcirc \kern-8pt\triangleright}\ \ \ v=10\ m/s}\end{array}[/tex]
Reemplazamos estos valores en la ecuación escalar anterior.
[tex]\begin{array}{c}\mathsf{d = v\times\: t}\\\\\\\mathsf{d = (5\:\dfrac{m}{s})\times\:(10\:s)}\\\\\\\mathsf{\:d = (5\:\dfrac{m}{\not \!s})\times\:(10\!\not \!s)}\\\\\\\mathsf{\boxed{\boxed{\boldsymbol{\mathsf{d = 50\:m}}}}}\end{array}[/tex]
Rpta. El móvil recorre 50 metros.
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