Respuesta :

Respuesta:

Explicación paso a paso:

Let's solve each equation step by step:

### a) \( (5x - 4)(2x - 3) - 5 = \)

First, expand the product:

\[ (5x - 4)(2x - 3) = 5x \cdot 2x + 5x \cdot (-3) + (-4) \cdot 2x + (-4) \cdot (-3) \]

\[ = 10x^2 - 15x - 8x + 12 \]

\[ = 10x^2 - 23x + 12 \]

Then, subtract 5:

\[ 10x^2 - 23x + 12 - 5 \]

\[ = 10x^2 - 23x + 7 \]

So, the solution is:

\[ 10x^2 - 23x + 7 \]

### b) \( 3(x^2 + 5) - (x^2 + 40) = \)

First, distribute 3 in the first term:

\[ 3(x^2 + 5) = 3x^2 + 15 \]

Then, subtract the second term:

\[ 3x^2 + 15 - (x^2 + 40) \]

\[ = 3x^2 + 15 - x^2 - 40 \]

\[ = 2x^2 - 25 \]

So, the solution is:

\[ 2x^2 - 25 \]

### c) \( x \cdot (5x - 4) - 2 \cdot (x^2 - x) = \)

First, distribute \( x \) in the first term:

\[ x(5x - 4) = 5x^2 - 4x \]

Then, distribute \( 2 \) in the second term:

\[ 2(x^2 - x) = 2x^2 - 2x \]

Now, subtract the second term from the first:

\[ 5x^2 - 4x - (2x^2 - 2x) \]

\[ = 5x^2 - 4x - 2x^2 + 2x \]

\[ = 3x^2 - 2x \]

So, the solution is:

\[ 3x^2 - 2x \]

### d) \( x^2 - (x - 1)^2 = \)

First, expand \( (x - 1)^2 \):

\[ (x - 1)^2 = x^2 - 2x + 1 \]

Then, subtract this from \( x^2 \):

\[ x^2 - (x^2 - 2x + 1) \]

\[ = x^2 - x^2 + 2x - 1 \]

\[ = 2x - 1 \]

So, the solution is:

\[ 2x - 1 \]

### e) \( 3x^2 - 2(x + 5) - (x + 3) = \)

First, distribute \( 2 \) in the second term:

\[ -2(x + 5) = -2x - 10 \]

Then, distribute the negative sign in the third term:

\[ -(x + 3) = -x - 3 \]

Now, combine all terms:

\[ 3x^2 - 2x - 10 - x - 3 \]

\[ = 3x^2 - 3x - 13 \]

So, the solution is:

\[ 3x^2 - 3x - 13 \]

### f) \( 3x^2 - 2(x + 5) - (x + 3) + 19 = \)

First, distribute \( 2 \) in the second term:

\[ -2(x + 5) = -2x - 10 \]

Then, distribute the negative sign in the third term:

\[ -(x + 3) = -x - 3 \]

Now, combine all terms including the constant:

\[ 3x^2 - 2x - 10 - x - 3 + 19 \]

\[ = 3x^2 - 3x + 6 \]

So, the solution is:

\[ 3x^2 - 3x + 6 \]

### g) \( x^2 - 4(x^2 + 3x - 1) = \)

First, distribute \( 4 \) in the second term:

\[ 4(x^2 + 3x - 1) = 4x^2 + 12x - 4 \]

Then, subtract this from \( x^2 \):

\[ x^2 - (4x^2 + 12x - 4) \]

\[ = x^2 - 4x^2 - 12x + 4 \]

\[ = -3x^2 - 12x + 4 \]

So, the solution is:

\[ -3x^2 - 12x + 4 \]