Respuesta :
Respuesta:
To determine the total momentum of the system consisting of the motorcyclist and the motorcycle, we need to calculate the individual momentums of each object and add them together.
**Individual Momentum Calculations:**
**Motorcyclist's Momentum:**
* Mass of motorcyclist (m_m) = 40 kg
* Velocity of motorcyclist (v_m) = Distance / Time = 25 m / 15 s = 5/3 m/s
Momentum of motorcyclist (p_m) = m_m * v_m = 40 kg * (5/3 m/s) = 200/3 kg m/s
**Motorcycle's Momentum:**
* Mass of motorcycle (m_mc) = 3.5 kg
* Velocity of motorcycle (v_mc) = Same as motorcyclist's velocity (v_m) = 5/3 m/s
Momentum of motorcycle (p_mc) = m_mc * v_mc = 3.5 kg * (5/3 m/s) = 35/6 kg m/s
**Total Momentum:**
Total momentum (p_total) = p_m + p_mc
p_total = (200/3 kg m/s) + (35/6 kg m/s)
p_total = 200/3 kg m/s + 35/6 kg m/s
**Combining Like Terms:**
p_total = (200 * 2) / (3 * 6) kg m/s + (35 * 3) / (6 * 3) kg m/s
p_total = 400/18 kg m/s + 105/18 kg m/s
p_total = (400 + 105) / 18 kg m/s
p_total = 505/18 kg m/s
**Therefore, the total momentum of the system consisting of the motorcyclist and the motorcycle is 505/18 kg m/s.**
Explicación: