Explicación:
I can't directly interact with your device to help you with that. However, I can provide you with some general information that may be helpful.
The image you sent shows a table of 134 algebraic equations. The equations are all in the form of polynomials, which are expressions that consist of one or more variables raised to non-negative integer powers, multiplied by coefficients, and added or subtracted together.
To solve an algebraic equation, you need to manipulate the equation in such a way that the variable you are solving for is isolated on one side of the equation. This can be done using a variety of techniques, such as adding or subtracting the same number to both sides of the equation, multiplying or dividing both sides of the equation by the same number, or using the distributive property.
Once the variable is isolated, you can solve for it by performing the inverse operation of the operation that was used to isolate it. For example, if the variable was multiplied by 2, you would divide both sides of the equation by 2 to solve for the variable.
Here are some examples of how to solve some of the equations in the table:
* Equation 1: $x^2 - 36 = 0$
Add 36 to both sides of the equation to get: $x^2 = 36$.
Take the square root of both sides of the equation to get: $x = \pm 6$.
Therefore, the solutions to the equation are $x = 6$ and $x = -6$.
* Equation 2: $m^2 + 2mx + x^2 = 0$
Factor the left side of the equation to get: $(m + x)^2 = 0$.
Take the square root of both sides of the equation to get: $m + x = 0$.
Subtract $x$ from both sides of the equation to get: $m = -x$.
Therefore, the solution to the equation is $m = -x$.
* Equation 3: $a^2 + a - ab - b = 0$
Factor the left side of the equation to get: $(a + b)(a - b) = 0$.
Therefore, the solutions to the equation are $a + b = 0$ and $a - b = 0$.
Solving these equations, we get $a = -b$ and $a = b$.
Therefore, the solutions to the equation are $a = -b$ and $a = b$.
I hope this helps!
