Respuesta:
Ejercicio 5
[tex]4x(2x - 1) = 3(2x - 1) \\ 8{x}^{2} - 4x = 6x - 3 \\ 8{x}^{2} - 10x + 3 = 0 \\ x = \frac{3}{4} \quad x = \frac{1}{2} [/tex]
Ejercicio 6
[tex] - 2 {x}^{2} (5x + 6) = \\ - 10 {x}^{3} - 12 {x}^{2} [/tex]
Ejercicio 7
[tex]5 {x}^{2} (3x - 7) = \\ 15 {x}^{3} - 35 {x}^{2} [/tex]
Ejercicio 8
[tex] - x( {x}^{2} + 7) = \\ - {x}^{3} + - 7x[/tex]
Ejercicio 9
[tex]4 {x}^{2} ( {x}^{2} - 3x - 5) = \\ 4 {x}^{4} - 12 {x}^{3} - 20 {x}^{2} [/tex]
