Es producto de radicales.
Se sabe que:
[tex]\sqrt{a} .\sqrt{b} =\sqrt{a.b}[/tex]
Entonces :
[tex]\sqrt{6} =\sqrt{3} .\sqrt{2}\\ \\\sqrt{8} =\sqrt{4} .\sqrt{2} =2\sqrt{2} \\\\\sqrt{3} =\sqrt{3}. \sqrt{1} =\sqrt{3}[/tex]
Nos piden:
[tex]=\sqrt{8} .\sqrt{6} .\sqrt{3} \\\\=2\sqrt{2}.\sqrt{3}.\sqrt{2} .\sqrt{3} \\\\=2.2.3\\\\=12[/tex]
