Suma algebraica
Ordenamos
Sumamos y restamos
[tex]\bf \dfrac{2}{3}n+ \dfrac{1}{4}n-2n-\dfrac{5}{4}n- \dfrac{5}{3}n+ \dfrac{3}{4}n+ \dfrac{2}{5}n-n+4n=\\ \\ \\\left( \dfrac{2}{3}n+ \dfrac{1}{4}n+ \dfrac{3}{4}n+ \dfrac{2}{5}n+4n\right)-\left(+2n+\dfrac{5}{4}n+ \dfrac{5}{3}n+n\right)= \\ \\ \\\left( \dfrac{40}{60}n+ \dfrac{15}{60}n+ \dfrac{45}{60}n+ \dfrac{24}{60}n+\dfrac{240}{60} n\right)-\left(+\dfrac{120}{60}n+\dfrac{75}{60}n+ \dfrac{100}{60}n+\dfrac{60}{60} n\right)=[/tex]
[tex]\bf \\ \\ \\\left( \dfrac{364}{60}n\right)-\left(\dfrac{355}{60}n\right)=\\ \\ \\ \dfrac{364-355}{60}n=\boxed{\boxed{\bf{ \dfrac{9}{60} n}}}[/tex]
Espero que te sirva, salu2!!!!
