Explicación paso a paso:
[tex]\frac{2}{x} +3\sqrt{y+1}=16....(2)\\ \frac{8}{x} -2\sqrt{y+1}=36....(3)[/tex]
[tex]\frac{4}{x} +6\sqrt{y+1}=32\\ \frac{24}{x} -6\sqrt{y+1}=108[/tex]
_______________
[tex]\frac{4}{x} +\frac{24}{x} =140\\\frac{4+24}{x} =140\\\frac{28}{x} =140\\x=\frac{28}{140}\\x=\frac{1}{5}[/tex]
Remplazamos para y :
[tex]\frac{2}{\frac{1}{5}} + 3\sqrt{y+1} =16\\10 +3\sqrt{y+1} = 16\\3\sqrt{y+1} = 16-10\\3\sqrt{y+1} = 6\\\sqrt{y+1} =\frac{6}{3} \\\sqrt{y+1} =2\\y+1= 2^{2} \\y+1 = 4\\y = 3[/tex]
Por lo tanto :
[tex]\frac{x}{y} = \frac{\frac{1}{5} }{3} = \frac{1}{15}[/tex]
RESPUESTA: c) 1/15
