Respuesta :
6x² - 17x - 3 = 0
Aplicamos formula general:
x = 17 ± √ [ (-17)² - 4(6)(-3) ]
2(6)
x = 17 ± 19
12
Luego, las raices serán:
x1 = (17 - 19)/12 = -1/6
x2 = (17 + 19)/12 = 3
Cs = conjunto solución = {-1/6 ; 3}
Eso es todo ;)
Aplicamos formula general:
x = 17 ± √ [ (-17)² - 4(6)(-3) ]
2(6)
x = 17 ± 19
12
Luego, las raices serán:
x1 = (17 - 19)/12 = -1/6
x2 = (17 + 19)/12 = 3
Cs = conjunto solución = {-1/6 ; 3}
Eso es todo ;)
6x^2 -17x -3 =0 factorizamos multiplicamos y dividimos la ecuacionpor el coeficiente de x^2 que es 6
[6^2x^2 -17(6x) -18]/6 =0
(6x - 18 )( 6x +1)]/6 =0
[6(x -3)(6x +1) ]/6 =0
(x-3 )(6x+1) =0
x -3
x =3
6x +1 =0
6x = -1
x = -1/6
solucion (3, -1/6)
[6^2x^2 -17(6x) -18]/6 =0
(6x - 18 )( 6x +1)]/6 =0
[6(x -3)(6x +1) ]/6 =0
(x-3 )(6x+1) =0
x -3
x =3
6x +1 =0
6x = -1
x = -1/6
solucion (3, -1/6)